0.5x^2+7x-10=0

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Solution for 0.5x^2+7x-10=0 equation:



0.5x^2+7x-10=0
a = 0.5; b = 7; c = -10;
Δ = b2-4ac
Δ = 72-4·0.5·(-10)
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{69}}{2*0.5}=\frac{-7-\sqrt{69}}{1} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{69}}{2*0.5}=\frac{-7+\sqrt{69}}{1} $

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